Issue
num_pixels_per_cell_one_axis = 5
num_cells_per_module_one_axis = 3
inter_cell_sep = 4
max_items_in_list = num_cells_per_module_one_axis * num_pixels_per_cell_one_axis + (num_cells_per_module_one_axis-1) * inter_cell_sep
print(max_items_in_list)
indices_to_retain = list(range(max_items_in_list))
indices_to_remove = indices_to_retain[num_pixels_per_cell_one_axis :: num_pixels_per_cell_one_axis + inter_cell_sep]
if inter_cell_sep == 2:
for k in range(0,len(indices_to_remove)):
indices_to_remove.append(indices_to_remove[k]+1)
if inter_cell_sep == 3:
for k in range(0,len(indices_to_remove)):
indices_to_remove.append(indices_to_remove[k]+1)
indices_to_remove.append(indices_to_remove[k]+2)
for k in indices_to_remove:
indices_to_retain.remove(k)
print(indices_to_remove)
print(indices_to_retain)
I want to find a way to loop inter_cell_sep for any positive number and as it increases the lines for appending the list also increases. The expected answer should be [0,1,2,3,4,9,10,11,12,17,18,19,20]
Solution
I think instead of using if statements for each value of inter_cell_sep you could loop through a range of inter_cell_sep. Here is what I came up with.
num_pixels_per_cell_one_axis = 5
num_cells_per_module_one_axis = 3
inter_cell_sep = 3
max_items_in_list = num_cells_per_module_one_axis * num_pixels_per_cell_one_axis + (num_cells_per_module_one_axis - 1) * inter_cell_sep
print(max_items_in_list)
indices_to_retain = list(range(max_items_in_list))
indices_to_remove = indices_to_retain[num_pixels_per_cell_one_axis:: num_pixels_per_cell_one_axis + inter_cell_sep]
for k in range(0, len(indices_to_remove)):
indices_to_remove.extend([indices_to_remove[k] + x for x in range(1, inter_cell_sep)])
for k in indices_to_remove:
indices_to_retain.remove(k)
print(indices_to_remove)
print(indices_to_retain)
Answered By - nickrl21 Answer Checked By - Gilberto Lyons (PHPFixing Admin)
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