Issue
I'm trying to make a job that saves the HTTP response as json in the database using the handle method, this is my code:
public function handle()
{
$syncedResults = $this->guzzleGet();
Rfm::truncate();
/**
* @var \Illuminate\Database\Eloquent\Model $rfm
*/
Rfm::create(['RFM' => $syncedResults]);
}
public function guzzleGet()
{
$aData = [];
$sCursor = null;
while($aResponse = $this->guzzleGetData($sCursor))
{
if(empty($aResponse['data']))
{
break;
}
else
{
$aData = array_merge($aData, $aResponse['data']);
if(empty($aResponse['meta']['next_cursor']))
{
break;
}
else
{
$sCursor = $aResponse['meta']['next_cursor'];
}
}
}
return json_encode($aData);
here is my model :
<?PHP
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
class Rfm extends Model
{
use HasFactory;
protected $fillable = ['RFM'];
}
And the migrations:
public function up()
{
Schema::create('rfms', function (Blueprint $table) {
$table->id();
$table->json('RFM');
$table->timestamps();
});
}
now I made a signature command to run the worker but every time it fail with this error in the log:
TypeError: Illuminate\Database\Grammar::parameterize(): Argument #1 ($values) must be of type array, string given, called in C:\xampp\htdocs\clv\vendor\laravel\framework\src\Illuminate\Database\Query\Grammars\Grammar.php on line 920 and defined in C:\xampp\htdocs\clv\vendor\laravel\framework\src\Illuminate\Database\Grammar.php:136
i wonder if I'm doing something wrong?!
Solution
i have found a workaround in the meanwhile:
just inserting the data using the Query Builder instead of eloquent, Like this:
public function handle()
{
$syncedResults = $this->guzzleGet();
Rfm::truncate();
/**
* @var \Illuminate\Database\Eloquent\Model $rfm
*/
DB::table('rfms')->insert(['RFM' => json_encode($syncedResults)]);
}
Answered By - Amjad Alarori Answer Checked By - Marie Seifert (PHPFixing Admin)
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