Issue
I want to get the profile's picture url. To get the name I do the following:
$fb = new \Facebook\Facebook([
'app_id' => '{app_id}',
'app_secret' => '{app_secret}',
'default_graph_version' => 'v2.5',
'default_access_token' => '{access_token}',
]);
$response = $fb->get('/me');
$name = $response->getGraphObject()->asArray();
$name = $name['name'];
echo $name;
With the same logic I tried to get the profile picture url with the following:
$fb = new \Facebook\Facebook([
'app_id' => '{app_id}',
'app_secret' => '{app_secret}',
'default_graph_version' => 'v2.5',
'default_access_token' => '{access_token}',
]);
$response = $fb->get('/me/picture');
$pic = $response->getGraphObject()->asArray();
$pic = $pic['url'];
echo $pic;
And it didn't work. From the graph explorer I know that what I am getting when I am calling the /me/picture which is this:
{
"data": {
"is_silhouette": false,
"url": "https://scontent.xx.fbcdn.net/ etc etc "
}
}
So I am sure that I am making the right call but I mess it up when I am trying to get the url. My thinking is am going to the data object but I can't get the url value. I also tried with the get field, but had no luck:
$pic = $response->getGraphObject()->asArray();
$pic->getField('url');
Removing the ->asArray() made no difference. Lastly I tried it this way but again no luck.
$object = $response->getGraphObject();
$pic = $object->asArray('data');
$pic = $pic['url'];
echo $pic;
Any help would be appreciated :)
Solution
So basically I discovered that there is a function called getGraphUser.
$response = $fb->get('/me?fields=picture');
$user = $response->getGraphUser();
$name = $user->getPicture();
echo $name['url'];
Answered By - Alex Spyr
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