[FIXED] How to add location to a post or a photo with facebook php sdk

Issue

This is driving me nuts.

Can anyone post a practical example on this? My gratitude for life:

1. Publish a post and add the related checkin/location info
2. publish a photo and add the related checkin/location info.

In both cases the user delegates the action to the app. We have the access token by prior.

Please no theory, a working coding snipper ;-)

I am particularly messed up because facebook asks a nested structures of objects and arrays

Any help would be really appreciated

Solution

Grab the $user instance

$user = $facebook->getUser();

Check if the logged in user is authenticated.

if ($user) {
  try {
    // Proceed 
    $user_profile = $facebook->api('/me');
  } catch (FacebookApiException $e) {
    error_log($e);
    $user = null;
  }
}

Present the login url with permissions needed for posting. Specifically the publish_streampermission as stated in the photo documentation http://developers.facebook.com/docs/reference/api/user/#photos

if ($user) {
  $logoutUrl = $facebook->getLogoutUrl();
} else {
  $loginUrl = $facebook->getLoginUrl(array(
             'scope' => 'read_stream,publish_stream,user_photos'
             ));
}

Place the me/photos call in a try/catch block to catch any exceptions that may occur.

    try {
        $facebook->setFileUploadSupport('http://yourapicallingwebsite.com/');
        $response = $facebook->api(
          '/me/photos/',
          'post',
          array(
            'message' => 'Testing the Photo Upload',
            'source' => '@/path/to/img',
            'place' => 'place_id' 
          )
        );
      }
   catch (FacebookApiException $e) {
       error_log('An error occurred posting the image');
   }

Check the response from the me/photos call

$photo_u = $facebook->api('/'.$response['id']);

Display it if your like

<img src=<?php echo $photo_u['picture'] ?>/>

Check the place name if you like

$photo_place = $photo_u['place'];
<span><?php echo $photo_place['name'] ?></span>

Answered By - phwd