[FIXED] Forming find conditions from multi word search query in CakePHP

Issue

I have products with multiple fields than can be searched (name, text, product code, etc).

What I want to do is explode the search string and make sure that every word is found somewhere at the record.

With one word I would normally do like:

'OR'=>array(
    'name LIKE'=>'%' . $oneword . '%',
    'text LIKE'=>'%' . $oneword . '%',
    'code LIKE'=>'%' . $oneword . '%',
 )

Now I feel that I have to make as many OR-arrays as search string has words and include them all in AND-array. I just don't know how to code it.

Solution

Something like this should do it

$conditions = array();
$search_terms = explode(' ', $search_string);
foreach($search_terms as $search_term){
    $conditions[] = array('Model.name Like' =>'%'.$search_term.'%');
    $conditions[] = array('Model.text Like' =>'%'.$search_term.'%');
    $conditions[] = array('Model.code Like' =>'%'.$search_term.'%');
}
$products = $this->paginate('Product', array('conditions' => array('OR' => $conditions)));

Edit: If all your search term must be present in any of the fields, it would be something like this:

$conditions = array();
$search_terms = explode(' ', $search_string);
foreach($search_terms as $search_term){
    $conditions[] = array('OR' => array('Model.name Like' =>'%'.$search_term.'%',
                                        'Model.text Like' =>'%'.$search_term.'%',
                                        'Model.code Like' =>'%'.$search_term.'%',
                                  )
                          );
}
$products = $this->paginate('Product', $conditions); 

Answered By - kaklon

Answer Checked By - Dawn Plyler (PHPFixing Volunteer)