Issue
I want to create a new dict with a loop but I don't find the way to push key and value in loop with append. I try something like this but I'm still searching the good way.
frigo = {"mangue" : 2, "orange" : 8, "cassoulet" : 1, "thon" : 2, "coca" : 8, "fenouil" : 1, "lait" : 3}
new_frigo = {}
for i, (key, value) in enumerate(frigo.items()):
print(i, key, value)
new_frigo[i].append{key,value}
Solution
There's already a python function for that:
new_frigo.update(frigo)
No need for a loop! dict.update(other_dict)
just goes and adds all content of the other_dict
to the dict
.
Anyway, if you wanted for some reason to do it with a loop,
for key, value in frigo.items():
new_frigo[key] = value
would do that. Using an i
here makes no sense - a dictionary new_frigo
doesn't have indices, but keys.
Answered By - Marcus Müller Answer Checked By - Terry (PHPFixing Volunteer)
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