[FIXED] How can I store multiple function as a value of the dictionary?

Issue

In the following code I try to store multiple functions as a value of the dictionary. This code doesn't work. The two functions are returned as a tuple. But I don't want to iter over the dictionary. I want to use a special key, and then I want the dictionary to run the two functions.

from functools import partial

def test_1(arg_1 = None):
     print "printing from test_1 func with text:", arg_1

def test_2(arg_2 = None):
     print "printing from test_2 func with text:", arg_2

dic = {'a':(partial(test_1, arg_1 = 'test_1'),
            partial(test_2, arg_2 = 'test_2'))}

dic['a']()

Solution

You can build a closure to do that like:

Code:

def chain_funcs(*funcs):
    """return a callable to call multiple functions"""
    def call_funcs(*args, **kwargs):
        for f in funcs:
            f(*args, **kwargs)

    return call_funcs

Test Code:

def test_1(arg_1=None):
    print("printing from test_1 func with text: %s" % arg_1)


def test_2(arg_2=None):
    print("printing from test_2 func with text: %s" % arg_2)


from functools import partial
dic = {'a': chain_funcs(partial(test_1, arg_1='test_1'),
                        partial(test_2, arg_2='test_2'))}

dic['a']()

Results:

printing from test_1 func with text: test_1
printing from test_2 func with text: test_2

Answered By - Stephen Rauch

Answer Checked By - Pedro (PHPFixing Volunteer)