[FIXED] How do i write a program that calculates the product of a number's digits that are different from another number i input?

Issue

I have to input 2 numbers, n and k, and find the product of n's digits which are different from k. Example: n = 1234, k=2, and the product should be 1 * 3 * 4;

    #include <iostream>

using namespace std;

int main()
{
    int n, k, p=1, digit;
    cin >> n >> k;

    while(true){
            digit= n % 10;

        if(digit != k){
            p = p * digit;
        }
        n = n/10;
    }
    cout << "Product of digits different from K is: " << p;
    return 0;
}

When i run it, after i input n and k, the program doesnt do anything else and just keeps the console open without an output.

Solution

The problem is the while(true). In this way the program stay in the loop for eternal. A possible solution can be this:

int main()
{
    int n, k, p=1, digit;
    cin >> n >> k;

    while( n > 0 ){
            digit= n % 10;

        if(digit != k){
            p = p * digit;
        }
        n = n/10;
    }
    cout << "Product of digits different from K is: " << p;
    return 0;
}

Answered By - Zig Razor

Answer Checked By - Cary Denson (PHPFixing Admin)