[FIXED] how to format integers so that it prints spaces before it if there are not three number

Issue

I want to print some sequence of number in a specific format. Like if there are 3 digits it will print the integer but if there are not 3 digits for example if there are two digits or one digit then it will make up spaces. For example:
__3 bench
_55 pencils
675 pens
I wanted to how can I format this. the numbers are always integers.

 for key, value in dict.items():
        print(f'{key:} {value}')

Solution

Something like this by giving width to your parameter to print:

for key, value in dict.items():
    print (f'{key:>3} {value}')

Output:

>
  3 bench
 45 pencils
675 pens

You can replace 3 with the maximum number of digits you might have in your data or even pass it dynamically :

width = 3
for key, value in dict.items():
    print (f'{key:>{width}} {value}')

Answered By - eshirvana

Answer Checked By - Dawn Plyler (PHPFixing Volunteer)