Issue
I'm a student and I know nothing about PHP. but I have to do one of my assignment using PHP.
Here is the problem which I faced. On my index page, there are 3 links that direct to 3 different forms. when the user chooses one form, then fill and submit it result.php file shows the output using values that the user enters in the form. all the 3 forms should germinate its result using the same result.php file.
I cannot figure out how to generate the result page by identifying which form the user selects. Here is my code,
form1.php
<!DOCTYPE html>
<html>
<head>
<title>PHP form handling</title>
</head>
<body>
<form name="form1" action="result.php" method="post">
<label for="pullDownMenu">Title</label>
<select name="pullDownMenu" id="pullDownMenu" size="1">
<option value="Mr">Mr</option>
<option value="Ms">Ms</option>
<option value="Mrs">Mrs</option>
<option value="Rev">Rev</option>
</select>
<p>Name: <input type="text" name="firstname" value="" /></p>
<p>Reg No: <input type="text" name="lastname" value="" /></p>
<p>Email Addr: <input type="text" name="Email" value="" /></p>
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
form2.php
<!DOCTYPE html>
<html>
<head>
<title>form 2</title>
</head>
<body>
<form name="form2" action="result.php" method="post">
<p>Registrationa no: <input type="text" name="RegNO" value="" /></p>
<p>NIC number <input type="text" name="NIC" value=""></p>
<p>Telephone number: <input type="text" name="Telephone" value="" /></p>
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
I tried the result.php file, but it didn't work. here is the result.php
<!DOCTYPE html>
<html>
<head>
<title>PHP demo</title>
</head>
<body>
<?php
if(!empty($_POST['form1'])){
$title=$_POST['pullDownMenu'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$Email = $_POST['Email'];
echo"<h1>student information</h1>";
echo'title is : ' . $title . '</br>';
echo 'first name is : '. $firstname . '</br>';
echo 'lastname is : '.$lastname;
}
if (!empty($_POST['form2'])) {
$regNo = $_POST['RegNO'];
$NIC = $_POST['NIC'];
$tel = $_POST['Telephone'];
echo "<p>Following details are saved to database</p>";
echo 'reg No\t:\t' . $regNo. '</br>';
echo 'NIC\t:\t' . $NIC. '</br>';
echo 'Tel No\t:\t' . $tel. '</br>';
}
?>
</body>
</html>
Solution
Consider using isset() to check for a specific variable. It can be better then checking with empty().
<!DOCTYPE html>
<html>
<head>
<title>PHP demo</title>
</head>
<body>
<?php
if(isset($_POST['form1'])){
echo "<h1>student information</h1>\r\n";
echo "title is : $_POST['pullDownMenu']<br />\r\n";
echo "first name is : $_POST['firstname']<br />\r\n";
echo "lastname is : $_POST['lastname']\r\n";
}
if (isset($_POST['form2'])) {
echo "<p>Following details are saved to database</p>\r\n";
echo "reg No\t:\t$_POST['RegNO']<br />\r\n";
echo "NIC\t:\t$_POST['NIC']<br />\r\n";
echo "Tel No\t:\t$_POST['Telephone']<br />\r\n";
}
?>
</body>
</html>
If you have more forms, consider using switch() instead of if().
Answered By - Twisty Answer Checked By - Pedro (PHPFixing Volunteer)
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