Issue
I understand that JavaScript objects, including arrays, are automatically passed by reference, so I have something like this:
class Thing {
constructor( ) {
this.letters = [ "A", "B" ];
this.numbers = [ 1, 2, 3 ];
this.change( this.letters, this.numbers );
}
change( _letters, _numbers ) {
let l = _letters;
let n = _numbers;
l = [ ];
n = 6;
}
}
var t = new Thing( );
console.log( t );
The log request shows that there has been no change to the properties of Thing. And yet, under different conditions that I can not recognise, I have accidentally modified passed parameters inside a function, and have had to use something like n = Array.from( _numbers ) to avoid modifying the source property. Would someone be able to explain what is happening, and why?
I would like to pass object properties by reference such that I can modify more than one related property in a single function call, and thereby reserve the return value for debugging purposes.
Thank you.
Solution
The issue is the scoping. When you declared with let, the declaration is scoped to the function change and you are also reassigning the block-scoped variables here:
l = [ ];
n = 6;
If you want to change the class properties, you can do:
change(_letters, _numbers) {
this.letters = _letters; // `this` scoped to class
this.numbers = _numbers; // `this` scoped to class
}
See the example:
// simple demo start
let numbers = [1, 2, 3];
let n = numbers;
n.push(4)
console.info(n, typeof n);
n = 6; // reassign n
console.info(n, typeof n, numbers);
// simple demo end
// refactored class
class Thing {
constructor() {
this.letters = ["A", "B"];
this.numbers = [1, 2, 3];
this.change(this.letters, this.numbers);
}
change(_letters, _numbers) {
let l = _letters; // `let` is scoped to `change()`
let n = _numbers; // `let` is scoped to `change()`
l = []; // only changes scoped l
n = 6; // only changes scoped n
}
changeFix(_letters, _numbers) {
this.letters = _letters; // `this` scoped to class
this.numbers = _numbers; // `this` scoped to class
}
}
var t = new Thing();
console.log(t);
t.change(['C'], [4]);
console.info(t);
t.changeFix(['C'], [4]);
console.info(t);
Answered By - Samuel Goldenbaum Answer Checked By - David Marino (PHPFixing Volunteer)
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