[FIXED] How to update value of key in nested dictionary?

Issue

items = [{'id': 1, 'language': 'English', 'name': 'Sarah', 'description': 'Blah blah'}, {'id': 2, 'language': 'English', 'name': 'Jessica', 'description': 'More blah'}]

d = {}
for item in items:

    language = item['language']
    id = item['id']
    name = item['name']
    description = item['description']

    d[language][id] = {'name': name, 'description': description}

print(d)

I'm expecting to see in output:

{'English': {1:{'name': 'Sarah', 'description': 'Blah blah'}, 2:{'name': 'Jessica', 'description': 'More blah'}}}

But unfortunately I'm getting KeyError:

So, the question is how to update/append value in nested dictionary? What I'm doing wrong?

Solution

d does not contain d["English"] which you try to create with d[language][id] = {'name': name, 'description': description} - hence the error.

---

You cannot create intermediate dictionaries "on the fly" if they do not exist - either check if they already exist and if not create them - or use dict.setdefault(key,default) to create the entry if it does not yet exist:

items = [{'id': 1, 'language': 'English', 'name': 'Sarah', 'description': 'Blah blah'},
         {'id': 2, 'language': 'English', 'name': 'Jessica', 'description': 'More blah'}]

d = {}
for item in items:
   
    language = item['language']
    idd = item['id']
    name = item['name']
    description = item['description']

    d.setdefault(language,{})[idd] = {'name': name, 'description': description}

print(d)

Output:

{'English': {1: {'name': 'Sarah', 'description': 'Blah blah'}, 
             2: {'name': 'Jessica', 'description': 'More blah'}}}

You can use collections.defaultdict as well if you come into performance problems using setdefault - which is slightly less fast.

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Related: Use cases for the 'setdefault' dict method

Answered By - Patrick Artner

Answer Checked By - Timothy Miller (PHPFixing Admin)