[FIXED] How do I catch system-level exceptions in Linux C++?

Issue

The following catch() is not called:

void test(void)
{
    int i=1,j=0,k;
    try
    {
        k = i/j;
    }
    catch(...)
    {
        ...handle it...
    }
}

Is there a way to catch this kind of exception?

Solution

below code implement __try/__except effect like in visual studio c++ or how to simulate __try/__except for gcc or g++

#include <stdio.h>
#include <signal.h>
#include <setjmp.h>

__thread jmp_buf * gThreadData; //thread local storage variable declare

void FPE_ExceptionHandler(int signal)
{
    printf("exception handler signalid=%d\n", signal);

    //jmp to setjmp_return and rc will equal to non zero
    longjmp(*gThreadData, 10001);
}

int main(int argc, char *argv[])
{
    //setup a callback function for access violation exception
    signal(SIGSEGV, (__sighandler_t)FPE_ExceptionHandler);

    //allocate a jmp_buf struct and assign it to thread local storage pointer
    gThreadData = (jmp_buf *)(new jmp_buf);

    //setjmp save current thread context
    int rc = setjmp(*gThreadData);

    //setjmp_return
    //first time, run to here rc will equal to 0
    if (rc == 0) {
        *(int*)0 = 1; //generate a exception
    }

    printf("return from exception\n");
    delete (jmp_buf *)gThreadData;
}

Answered By - Darwin Zou

Answer Checked By - Pedro (PHPFixing Volunteer)