Issue
I'm trying to solve a problem on a competitive programming book where the output only appears after entering in the last input. I seem to have gotten the logic down but I'm still confuse as to how to do the input/output portion.
Here is the code:
#include <bits/stdc++.h>
int main()
{
std::ios_base::sync_with_stdio(false);
std::cin.tie(NULL);
std::vector<int>soundex;
std::string word;
for(int i = 0; i < word.length(); i++)
{
if (word[i] == 'B'|| word[i] == 'F' || word[i] == 'P' || word[i] == 'V')
{
soundex.push_back(1);
}
if (word[i] == 'C' || word[i] == 'G' || word[i] == 'J' || word[i] == 'K' || word[i] == 'Q' || word[i] == 'S' || word[i] == 'X' || word[i] == 'Z')
{
soundex.push_back(2);
}
if (word[i] == 'D' || word[i] == 'T')
{
soundex.push_back(3);
}
if (word[i] == 'L')
{
soundex.push_back(4);
}
if (word[i] == 'M' || word[i] == 'N')
{
soundex.push_back(5);
}
if (word[i] == 'R')
{
soundex.push_back(6);
}
}
for (int j = 0; j < soundex.size(); j++)
{
if (soundex[j] == soundex[j+1])
{
soundex.erase(soundex.begin() + 1);
}
std::cout << soundex[j];
}
std::cout << "\n";
return 0;
}
It behaves like this:
Input:
KHAWN
Output:
25
Input:
PFISTER
Output:
1236
Input:
BOBBY
Output:
11
But I need it to behave like this, per the instructions of the problem:
Input:
KHAWN
PFISTER
BOBBY
Output:
25
1236
11
Solution
Use while(cin >> word){ ... your code ... }
to read until EOF (End Of File) in case every line only contains a word (no spaces allowed). You can keep the output as it is.
Answered By - Eloy Pérez Torres Answer Checked By - Marilyn (PHPFixing Volunteer)
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