Issue
I'm looking for a loop similar to this for converting ASCII to decimal then decimal to binary string: string = input("Enter message: ")
#Convert string from ASCII to Decimal
A_string = [ord(c) for c in string]
print(A_string)
# add 1 to ASCII value
B_string = A_string
for i in range(len(B_string)):
B_string[i] = B_string[i] + 1
print(B_string)
#Decimal to Binary
decimal = B_string
remainder = decimal
Binary_string = decimal
for i in range(len(decimal)):
remainder[i] = int(decimal[i])
remainder[i] %= 2
decimal[i] = decimal[i] // 2
Binary_string[i] = str(remainder[i] + Binary_string[i])
print(Binary_string)
What I'm NOT looking for are things like this:
res = "".join(f"{ord(shiftedChar):08b}")
shiftedChar
I'm looking for BASIC OLD SCHOOL techniques... programming what's actually happening using basic division, multiplication, powers, etc
Solution
From https://stackoverflow.com/a/7397195/1675501
First, you need to strip the 0b prefix, and left-zero-pad the string so it's length is divisible by 8, to make dividing the bitstring up into characters easy:
bitstring = bitstring[2:]
bitstring = -len(bitstring) % 8 * '0' + bitstring
Then you divide the string up into blocks of eight binary digits, convert them to ASCII characters, and join them back into a string:
string_blocks = (bitstring[i:i+8] for i in range(0, len(bitstring), 8))
string = ''.join(chr(int(char, 2)) for char in string_blocks)
If you actually want to treat it as a number, you still have to account for the fact that the leftmost character will be at most seven digits long if you want to go left-to-right instead of right-to-left.
Answered By - Rusty Robot Answer Checked By - Mary Flores (PHPFixing Volunteer)
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