Issue
I have created an initial version, however you have to type the individual inputs for each output. I want to be able to just type into one input box and then it calculates all other outputs. How would i do this?
This is the code i have currently, im very very new to this :)
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber /0.7).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="RETAIL"></output> Retail
</form>
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber *1).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="Schools & CDC's"></output> Schools & CDC's
</form>
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber / 0.7 -(a.valueAsNumber / 0.7 / 100*40)).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="Trade - Band A" Math.round></output> Trade - Band A
</form>
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber *1).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="Trade - Band B"></output> Trade - Band B
</form>
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber / 0.7 -(a.valueAsNumber / 0.7 / 100*20)).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="Trade - Band C" Math.round></output> Trade - Band C
</form>
<form onsubmit="return false" oninput="o.value = (a.valueAsNumber / 0.7 -(a.valueAsNumber / 0.7 / 100*10)).toFixed(0)" <br>
NHS <input name="a" id="a" type="number" step="any" placeholder="NHS" <br> TO <input name="o" id="o" type="number" for="a" placeholder="Trade - Band D" Math.round></output> Trade - Band D
</form>https://jsfiddle.net/5gpLbj80/2/
Solution
First piece of advice would be to remove all of those inline event handlers.
Attach a named function, then do all of your grunt-work inside it.
By using addEventListener to connect the two, the function 'knows' which element it's attached to. That is to say, we can simply use this.value to get it's value, rather than having to use document.getElementById('nhs').value
"use strict;"
function byId(id){return document.getElementById(id)}
window.addEventListener('load', onLoaded, false);
function onLoaded(evt)
{
let input = byId('myInput');
input.addEventListener('input', onInputReceived, false);
}
function onInputReceived(evt)
{
let outputs = [byId('output1'), byId('output2'), byId('output3')];
let value = parseFloat(this.value);
if (!isNaN(value))
{
outputs[0].textContent = value * 2;
outputs[1].textContent = value * 3;
outputs[2].textContent = parseInt( (value * 3)/4 );
}
else
{
outputs[0].textContent =
outputs[1].textContent =
outputs[2].textContent = "*invalid input (enter a number)*";
}
}<label>Enter data: <input id='myInput'/></label><br>
<ul>
<li id='output1'></li>
<li id='output2'></li>
<li id='output3'></li>
</ul>Alternate snippet
<!doctype html>
<html>
<head>
<script>
"use strict;"
function byId(id){return document.getElementById(id)}
window.addEventListener('load', onLoaded, false);
function onLoaded(evt)
{
let input = byId('myInput');
input.addEventListener('input', onInputReceived, false);
}
function onInputReceived(evt)
{
let outputs = [byId('output1'), byId('output2'), byId('output3')];
let value = parseFloat(this.value);
if (!isNaN(value))
{
outputs[0].textContent = value * 2;
outputs[1].textContent = value * 3;
outputs[2].textContent = parseInt( (value * 3)/4 );
}
else
{
outputs[0].textContent =
outputs[1].textContent =
outputs[2].textContent = "*invalid input (enter a number)*";
}
}
</script>
</head>
<body>
<label>Enter data: <input id='myInput'/></label><br>
<ul>
<li id='output1'></li>
<li id='output2'></li>
<li id='output3'></li>
</ul>
</body>
</html>
Answered By - enhzflep Answer Checked By - Gilberto Lyons (PHPFixing Admin)
Posts
0 Comments:
Post a Comment
Note: Only a member of this blog may post a comment.