Issue
I currently have a populated list full of nodes in a path from one node to another. I need to stylize the printing of the path as such:
node -> node -> node -> node ->
node -> node
I currently have this code to do so:
if len(path) %4 == 0:
for i in range(0, len(path)):
if i+1 % 4 == 0:
print(print_queue[0]+' -> '+print_queue[1]+' -> '+print_queue[2]+' -> '+print_queue[3]+' -> ')
print_queue = []
else:
print_queue.append(path[i])
if len(path) %4 == 1:
path.append(' ')
for i in range(0, len(path)):
if path[i] == ' ':
break
if i+1 % 4 == 0:
print(print_queue[0]+' -> '+print_queue[1]+' -> '+print_queue[2]+' -> '+print_queue[3]+' -> ')
print_queue = []
else:
print_queue.append(path[i])
if len(path) %4 == 2:
path.append(' ')
for i in range(0, len(path)):
if path[i] == ' ':
break
if i+1 % 4 == 0:
print(print_queue[0]+' -> '+print_queue[1]+' -> '+print_queue[2]+' -> '+print_queue[3]+' -> ')
print_queue = []
else:
print_queue.append(path[i])
if len(path) %4 == 3:
path.append(' ')
for i in range(0, len(path)):
if path[i] == ' ':
break
if i+1 % 4 == 0:
print(print_queue[0]+' -> '+print_queue[1]+' -> '+print_queue[2]+' -> '+print_queue[3]+' -> ')
print_queue = []
else:
print_queue.append(path[i])
if print_queue != []:
if len(print_queue) == 1:
print(print_queue[0])
if len(print_queue) == 2:
print(print_queue[0]+' -> '+print_queue[1])
if len(print_queue) == 3:
print(print_queue[0]+' -> '+print_queue[1]+' -> '+print_queue[2])
But the path is not being printed. The path list is populated, but the program does not give any output.
What do I need to change in order for this path to print?
Solution
It looks like you want to print each element in the path with " -> " between them.
print(" -> ".join(path))
should print them that way.
If you want a " -> " on the end too, just add one on the end in the print statement
print(" -> ".join(path) + " -> ")
so a path of ["a", "b", "c"]
will print a -> b -> c ->
If you want it to break on multiples of 4 nodes you can break the array into chunks of 4 first
path = ["a", "b", "c", "d", "e"]
print(" -> \n".join([" -> ".join(path[i:i+4]) for i in range(0, len(path), 4)]))
which will print
a -> b -> c -> d ->
e
Answered By - Ryan White Answer Checked By - Katrina (PHPFixing Volunteer)
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