Issue
Hı gusy! I am trying to drop ajax post function to one and use it on whole site with different url on each page.
This is my original function and how it works :
<button type="button"class="submit">send</button>
$(document).ready(function (){
$('.submit').on("click", function(e){
e.preventDefault();
var form = $(this).closest('form');
$.ajax({
type:'POST',
url:'ActionPage.php',
data:form.serialize(),
success:function(vardata){
var json = JSON.parse(vardata);
if(json.status == 101){
alert(json.msg);
window.location.replace("/");
} else {
alert(json.msg);
console.log(json.msg);
}
}
});
});
});
Exp: I have multiple forms in some pages, so I need to use $(this).closest('form');
to post each form.
This is what I want to do, original function will be in scripts and included in page :
function ajaxLoader(url) {
var form = $(this).closest("form");
$.ajax({
type:"POST",
"url" : url,
data:form.serialize(),
success:function(vardata){
var json = JSON.parse(vardata);
if(json.status == 101){
alert(json.msg);
window.location.replace("/");
} else {
alert(json.msg);
console.log(json.msg);
}
}
});
}
And on the page I want to call it like this :
$(document).ready(function (){
$('.submit').on("click", function(e){
e.preventDefault();
ajaxLoader("ActionPage.php", true);
});
});
I getting undefined message on all cases when I click send button, when I move $(this).closest("form");
to second function then I get undefined form error.
I have searched on site there are similar question but none of them has usefull answer. example : this one
Solution
How this
is scoped is based on the context of how it is called. You can change what this is with call/apply/bind. Basic example below.
function ajaxLoader(url) {
console.log(this, url)
var form = $(this).closest("form");
console.log(form[0]);
}
$(document).ready(function (){
$('.submit').on("click", function(e){
e.preventDefault();
ajaxLoader.call(this, "ActionPage.php");
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="foo">
<button class="submit">Click</button>
</form>
Answered By - epascarello Answer Checked By - Cary Denson (PHPFixing Admin)
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