[FIXED] How to pass arguments to bash script from a cpp program

Issue

I've forked a child process which then calls a bash script using execv, the way i'm passing command line arguments to the script, It does not print first argument on doing echo $1 inside the script.

std::string s = std::to_string(c_no);    
char *args[] = {(char *)s.c_str(), NULL};

pid_t pid = fork();
if(pid == 0){
    execv("./ckpnt.sh", &args[0]);
}

consider c_no to be any integer.

What is the correct way to do this?

I've already refrenced this link How to pass command line arguments from C program to the bash script? but this answer uses system system call and i try to not use that.

Solution

First argument passed to a program is its name so currently your number ends up in $0. args should be:

char *args[] = {"./ckpnt.sh", (char *)s.c_str(), NULL};

Answered By - Botje

Answer Checked By - Pedro (PHPFixing Volunteer)