[FIXED] How to print while waiting for input?

Issue

def receivedata(self):
    while True:
        data = self.soc.recv(1024)
        if data != "" or data != '' or data != "":
            sys.stdout.write("Recv>> ")
            sys.stdout.write(data)
            sys.stdout.flush()
            if data == "Server Shutdown":
                self.soc.close()
        elif not data:
            continue
def senddata(self):
    while True:
        try:
            sys.stdout.write("Send>> ")
            msg = sys.stdin.readline()
            self.soc.send(msg)
        except socket.error:
            sys.stdout.write("Socket Connection Timed Out")

This is part of my client code of python, and what I expect from this is while this waits for user input, it prints what it receives from server.

However, client does not print anything when it is waiting for user input — it only prints when something has been entered by user.

Is there a way that I could change this so that it prints even when it is waiting for user input?

Solution

If your program needs to wait on 2 separate events (user input and incoming socket data), you'll have to use threads, something like:

recv_thread = threading.Thread(target=receivedata)
recv_thread.setDaemon(True)
recv_thread.start()
senddata()

Couple of things about the code:

• when socket.error is encountered it can be something other than timeout.
• at one point you will need to exit the while loop from senddata (when the user input a certain text? or) in case of exception.
• also add exception handling in receivedata

• if statement in receivedata is not OK. you could replace it to:

  if data:
      ...if statements...
  

Answered By - CristiFati

Answer Checked By - David Goodson (PHPFixing Volunteer)