[FIXED] How do I detect the EOF parser error from within the code?

Issue

The Code is for a GUI Calculator. How do I detect the EOF parsing error from within my code?

Code:

def btnEqualsInput():
    global operator
    if operator!='':
        sumup = str(eval(operator))
        text_Input.set(sumup)
        operator =""

Output when I click '=' with 3* in textbox

    sumup = str(eval(operator))
  File "<string>", line 1
    3*
     ^
SyntaxError: unexpected EOF while parsing

I want to display "Error!" in the calculator display whenever user presses Equals on wrong syntax in the textbox.

Solution

Just catch the exception:

def btnEqualsInput():
    global operator
    if operator!='':
        try:
            sumup = str(eval(operator))
            text_Input.set(sumup)
            operator =""
        except SyntaxError as e:
            print("Error!",str(e)) #e contains the type of message, for example  unexpected EOF while parsing

You can parse the error string as well if you want to do something specific (for EOF for example, "EOF" in str(e) will be true)

Answered By - kabanus

Answer Checked By - Marilyn (PHPFixing Volunteer)