[FIXED] How to distinguish empty struct from one char?

Issue

I'm trying to implement own functor and faced with empty capture lambdas. How to distinguish empty struct from one char? Is there are any "real" size at compile time? I want just ignore empty lambdas to prevent useless allocations.

struct EmptyStruct {};
struct CharStruct { char c; };


int main()
{
    char buffer1[sizeof(EmptyStruct)]; // size 1 byte
    char buffer2[sizeof(CharStruct)]; // size 1 byte
}

Solution

You cannot do that with sizeof(), use std::is_empty, like this:

#include <iostream>
#include <type_traits>

struct EmptyStruct {};
struct CharStruct { char c; };
int main(void)
{
  std::cout << std::boolalpha;
  std::cout << "EmptyStruct " << std::is_empty<EmptyStruct>::value << '\n';
  std::cout << "CharStruct " << std::is_empty<CharStruct>::value << '\n';
  return 0;
}

Output:

EmptyStruct true
CharStruct false

as @RichardCritten commented.

Answered By - gsamaras

Answer Checked By - Candace Johnson (PHPFixing Volunteer)