[FIXED] How can I catch the following groups with a regex?

Issue

Hello I have the following two strings

txt = '/path/to/photo/file.jpg'
txt = '/path/to/photo/file_crXXX.jpg'

in the second string, XXX is a long variable path with information in the name because that is processed.

I want to extract the name 'file' in both path

In order to this, I tried the following code

re.search(".*/(.*)\.jpg", txt).group(1)
re.search(".*/(.*)_cr.*", txt).group(1)

But when I try to combine in one expression with the following code

re.search(".*/(.*)(_cr.*)|(\.jpg)*", txt).group(1)
re.search(".*/(.*)(\.jpg)|(_cr.*)", txt).group(1)

Doesn't work properly, so how can I do this?

Thanks

Solution

The problem was that you had captured a group that should not need to be captured, but the .*/(.*)(\.jpg)|(_cr.*) was closer to the answer. Please use this regex to capture only the filename or its prefix.

([^/]*?)(?:\.jpg|_cr.*)$

Also, see the regex demo

import re

paths = ["/path/to/photo/file.jpg", "/path/to/photo/file_crXXX.jpg"]
for path in paths:
    print(re.search(r"([^/]*?)(?:\.jpg|_cr.*)$", path).group(1))

Answered By - Artyom Vancyan

Answer Checked By - Mildred Charles (PHPFixing Admin)