[FIXED] How to extract the password from this string in bash: "--db_host db --db_password $£é5+dd/gcç# --db_name zorgl"?

Issue

I have tried this on Debian, but it fails:

echo "--db_host db --db_password $£é5+dd/gcç# --db_name zorgl" | sed -e "s/^.*db_password *\([^ ]+\) +.*$/\1/"

Result (no match):

--db_host db --db_password $£é5+dd/gcç# --db_name zorgl

Expected result:

$£é5+dd/gcç#

Solution

Using sed

$ sed -E 's/.*db_password ([^ ]*).*/\1/' input_file
$£é5+dd/gcç#

Answered By - HatLess

Answer Checked By - Senaida (PHPFixing Volunteer)