Issue
I am new to Laravel. I was practicing setting up a blog in Laravel 6. I have a layout.blade.php file where all the basic HTML is written. In the content section of the layout.blade file, I want to @include other blade file depending on the controller and method name.
I have 2 controllers, HomeController and ArticleController. In HomeController file, there is a method index() which returns the view home.blade.php. Again, home.blade.php @extends layout.blade.php. Now I want to know which controller and method called the view file inside from layout.blade.php file.
I want something like this-
<!-- This is layout.blade.php file -->
<html>
<head>
</head>
<body>
@if (Controller == HomeController AND Method == index)
@include('home')
@endif
@if (Controller == ArticleController AND Method == index)
@include('articles')
@endif
</body>
</html>
I didn't find any answer on Google. I got some questions in StackOverflow, but they have very confusing answers and those versions are older also.
Thank you.
EDIT 1:
- Due to the low reputation score, I cannot reply in comments. As I am new, I know some basic tags of blade, so if there is any other solution to achieve this, please share it with me.
- I found Get Laravel 5 controller name in view before making this question. But I don't think it answers my question.
- I know
Controller == HomeController AND Method == indexis crazy. I just illustrated what I need. I know basic@yieldand@sectiontags, but I don't want to use this in my case. Because, if I make a card/home section entirely in a different file, I can call it in other files later. If I use@yield, I will have to use@sectionin different files also, which I don't want to do.
Solution
Route::currentRouteAction() method seems to be what you want. It's in the api documentation.
string|nullcurrentRouteAction()Get the current route action.
Return Value
string|null
https://laravel.com/api/6.x/Illuminate/Routing/Router.html#method_currentRouteAction
Answered By - IGP Answer Checked By - Marie Seifert (PHPFixing Admin)
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