[FIXED] How to pass multiple variables as input in shell script in non-interactive way

Issue

I am trying to make this interactive script take inputs in a non-interactive way by declaring $username and $password variables in bash env and pass them as inputs to the script. By running ./input.sh <<< "$username"

#!bin/bash
read username
read password
echo "The Current User Name is $username"
echo " The  Password is $password"  

is there a way to pass both the variables as input? Because with what I have tried it only takes one input this way.

Solution

Easiest way would be something like that:

#!/bin/bash
echo "The Current User Name is $1"
echo "The Password is $2"

$1 represents the first given argument and $2 the second.

[user@vm ~]$ input.sh "user" "password"

Inside the quotation marks ("") put the argument you want to pass.

For more professional/robust solution check this out: Redhat: Bash Script Options/Arguments

Answered By - Bata94

Answer Checked By - Gilberto Lyons (PHPFixing Admin)