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Tuesday, December 13, 2022

[FIXED] How do you format an unsigned long long int using printf?

 December 13, 2022     c, format-specifiers, long-long, printf, syntax     No comments   

Issue

#include <stdio.h>
int main() {
    unsigned long long int num = 285212672; //FYI: fits in 29 bits
    int normalInt = 5;
    printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt);
    return 0;
}

Output:

My number is 8 bytes wide and its value is 285212672l. A normal number is 0.

I assume this unexpected result is from printing the unsigned long long int. How do you printf() an unsigned long long int?


Solution

Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).

printf("%llu", 285212672);


Answered By - John Downey
Answer Checked By - Marilyn (PHPFixing Volunteer)
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