Issue
In following bash script I'm trying to assign a value from a json object to a variable.
#!/bin/bash
json_data='{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}'
echo json_data:
echo $json_data
echo country_code:
echo $json_data | jq '.country_code'
echo country_name:
echo $json_data | jq '.country_name'
cc=$json_data | jq '.country_code'
echo cc:
echo $cc
cn=$($json_data | jq '.country_name')
echo cn:
echo $cn
Just echoing the expressions works. Assigning the value of the expressions to variables cc or cn doesn't.
$ ./test.sh
json_data:
{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}
country_code:
"GB"
country_name:
"United Kingdom"
cc:
./test.sh: line 19: {"ip":"1.2.3.4",: command not found
cn:
$
I thought that wrapping an expression in $(...) gave the functionality I need, but that results in an error.
Could anyone advise as to the correct syntax?
Solution
I thought that wrapping an expression in $(...) gave the functionality
You did not wrap enough. Wrap the whole expression, including echo
.
cn=$(echo "$json_data" | jq '.country_name')
Remember to quote variable expansions. Check your script with shellcheck - shellcheck will notify you of many problems.
You can put anything inside $(...)
, maybe this will clear it:
cn=$(
echo "$json_data" | jq '.country_name'
)
Answered By - KamilCuk Answer Checked By - Senaida (PHPFixing Volunteer)
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