Issue
How do I accomplish something like the following in Bash?
if ("$a" == "something" || ($n == 2 && "$b" == "something_else")); then
...
fi
Solution
You almost got it:
if [[ "$a" == "something" || ($n == 2 && "$b" == "something_else") ]]; then
In fact, the parentheses can be left out because of operator precedence, so it might also be written as
if [[ "$a" == "something" || $n == 2 && "$b" == "something_else" ]]; then
Answered By - Niklas B. Answer Checked By - Timothy Miller (PHPFixing Admin)
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