Issue
I have two lists of sets, let's say: [{1, 2, 3}, {4, 5}, {6, 7}] and [{1, 2}, {3, 4}, {5, 6, 7}]
No set in the list has the same element and the sum of all sets in both lists is the same. The function should check if the sets in both lists had the same elements. If there were some differences, put them in another set.
So above example should return: [{1, 2}, {3}, {4}, {5}, {6, 7}]
I work on large sets so I would need this function to be as effective as possible.
Here is the example code and how I would like it to work:
def mergeSets(x, y):
out = set()
for i in x:
out = out.union(i)
# this allows me to get the set of all elements but here where my mind stops working
# the problem sounds simple but thinking hours I can not think of good algorythm for this issue :(
# I found set.intersection() function but it works on single sets only, not lists of sets
return out
x = mergeSets([{1, 2, 3}, {4, 5}, {6, 7}], [{1, 2}, {3, 4}, {5, 6, 7}])
print(x)
# [{1, 2}, {3}, {4}, {5}, {6, 7}]
x = mergeSets([{1, 2}, {3, 4, 5, 6, 7}, {8}], [{1}, {2, 3, 4}, {5, 6, 7, 8}])
print(x)
# [{1}, {2}, {3, 4}, {5, 6, 7}, {8}]
EDIT: the data doesn't have to be sorted and may be even of different types than integer
EDIT2: the input lists don't have to be sorted so sets may appear in random order
Solution
Given that each value occurs in exactly two sets (one per input list), you could collect the index pairs for each value, where an index pair gives an indication in which two sets (at which indexes in both lists) the value occurs.
Unique pairs indicate unique sets in the output, so a dictionary of such pairs can serve to populate the result:
from collections import defaultdict
def merge_sets(lista, listb):
index_in_a = {
val: idx
for idx, elem in enumerate(lista) for val in elem
}
set_by_key = defaultdict(set)
for idx, elem in enumerate(listb):
for val in elem:
set_by_key[(index_in_a[val], idx)].add(val)
return list(set_by_key.values())
This looks O(n) to me.
NB: since the order of iteration over a set is not defined, the order of the output can look a bit mingled, but I assume the order of where sets appear in the output is not significant.
Answered By - trincot Answer Checked By - Dawn Plyler (PHPFixing Volunteer)
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