Issue
I have a list of key binds in a class like so:
self.key_bind_list = [["A", "B"], ["C"], ["SHIFT", "NUM6", "NUM7"], ["A", "B"], ["A", "B", "C"]]
*in this case a duplicate should be detected by the sublists ["A", "B"], but not by ["A", "B"] and ["A", "B", "C"]
And I'd like to check if there are any duplicates on the main list (assuming that the keys within each sublist are uniques, order is not important, and I don't need to know which ones that aren't unique)
I've tried using the set method in the following:
if(len(self.key_bind_list) != len(set(self.key_bind_list))):
Which gave me a unhashable type: 'list' error.
Solution
Assuming you just want to check if there are duplicates, and print out which sublists contain duplicates, you could use an approach with a list that contains set elements, such as so:
key_bind_list = [["A", "B"], ["C"], ["SHIFT", "NUM6", "NUM7"], ["B", "A"], ["A", "B", "C"]]
seen = []
for i, sublist in enumerate(key_bind_list):
s = set(sublist)
if s in seen:
print(f'index {i}: there are duplicates in {sublist}')
seen.append(s)
Output:
index 3: there are duplicates in ['B', 'A']
To just return a bool value if any sublist in a list is a duplicate (regardless of order) of another sublist, you could do something like this:
def has_duplicates(L: list[list]) -> bool:
seen = []
for sublist in L:
s = set(sublist)
if s in seen:
return True
seen.append(s)
return False
print(has_duplicates(key_bind_list))
Answered By - rv.kvetch Answer Checked By - Mary Flores (PHPFixing Volunteer)
Posts
