[FIXED] Why there is an unbound variable error warning by IDE in this simple python function

Issue

Very simple question, but I can't find the answer to it. My IDE vs code (pylance) give me the warning/hint for a being possibly unbound. Why is this? How do I fix it?

def f():
    for i in range(4):
        a = 1
        print(a)

    return a

Solution

Because range(4) might be something empty (if you overwrite the built-in range), in which case the loop body will never run and a will not get assigned. Which is a problem when it's supposed to get returned.

Maybe you can tell your IDE to ignore this and not show the warning. Or assign some meaningful default to a before the loop.

Answered By - superb rain

Answer Checked By - David Marino (PHPFixing Volunteer)

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