[FIXED] Where to put the `@unchecked` to suppress "pattern match on a refinement type is unchecked"?

Issue

When I run the following code snippet with scala

import scala.language.reflectiveCalls

def foo(a: Option[Any]): Option[Any] = {
  a.filter {
    case x: { def bar: Boolean } => x.bar
  }
}

object Bar {
  def bar: Boolean = true
}

println(foo(Some(Bar)))

I get a warning

warning: a pattern match on a refinement type is unchecked

I've tried the following:

@unchecked case x: { def bar: Boolean } => x.bar
case (@unchecked x): { def bar: Boolean } => x.bar
case (x @unchecked): { def bar: Boolean } => x.bar
case x: @unchecked { def bar: Boolean } => x.bar
case x: { def bar: Boolean } @unchecked => x.bar
case (x: { def bar: Boolean } @unchecked) => x.bar
case x: ({ def bar: Boolean } @unchecked) => x.bar
case x: { def bar: Boolean } => (x @unchecked).bar
case x: { def bar: Boolean } => (x: { def bar: Boolean } @unchecked).bar

None of those work. This also doesn't work:

  a.filter { any => (any: @unchecked) match {
    case x: { def bar: Boolean } => x.bar
  }}

How do I suppress this warning?

---

Somewhat related links

This answer seems to use the @unchecked successfully inside Some(...), but I don't see how to use it with filter.

Solution

An additional pair of round parentheses around the { def ... } is required:

case x: ({ def bar: Boolean }) @unchecked => x.bar

With the additional parentheses, it compiles just fine, without any warnings.

---

This seems to be similar to the syntax for the "classical type-lambdas", where

({ type Lam[X] = Foo[X] })#Lam

worked, whereas

{ type Lam[X] = Foo[X] }#Lam

didn't.

Answered By - Andrey Tyukin

Answer Checked By - Pedro (PHPFixing Volunteer)

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